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327 lines
6.7 KiB
Markdown
327 lines
6.7 KiB
Markdown
+++
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author = "Wxn"
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title = "2024-04-20七大排序算法+层序遍历"
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date = "2024-04-20"
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description = "Please read me first."
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tags = [
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"Dilay",
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]
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categories = [
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"面试复盘",
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]
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+++
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This article offers a sample of basic Markdown.
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<!--more-->
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# 正文开始
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https://www.nowcoder.com/login?callBack=%2Fprofile%2F319706329%2FcodeBookDetail%3FsubmissionId%3D416948138
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## 1.冒泡排序(从小到大)
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```cpp
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#include <iostream>
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#include <vector>
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using namespace std;
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//冒泡排序
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vector<int> MySort(vector<int>& arr) {
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int n = arr.size();
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for(int i = 0; i< n-1;i++)//冒泡排序和选择排序都是0~n-1轮
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{
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for(int j = 0 ; j <n -i-1 ;j++)
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{
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if(arr[j] <= arr[j+1])continue;
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int t = arr[j];
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arr[j] = arr[j+1];
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arr[j+1] = t;
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}
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}
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return arr;
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}
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int main()
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{
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vector<int> arr{5,2,3,1,4};
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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cout<<" "<<endl;
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MySort(arr);
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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return 0;
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}
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```
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## 2.选择排序(从小到大)
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```cpp
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#include <iostream>
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#include <vector>
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using namespace std;
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//选择排序
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vector<int> MySort(vector<int>& arr) {
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int n = arr.size();
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for(int i = 0; i< n-1;i++)
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{
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//只有这个是需要改变的
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int min_idx = i;
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for(int j = i+1 ; j < n; j++)//找到[i,n-1]范围内,最小数的下标
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{
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if(arr[j] <arr[min_idx])min_idx = j;
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}
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int t = arr[i];
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arr[i] = arr[min_idx];
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arr[min_idx] = t;
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}
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return arr;
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}
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int main()
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{
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vector<int> arr{5,2,3,1,4};
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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cout<<" "<<endl;
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MySort(arr);
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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return 0;
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}
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```
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## 3.插入排序
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```cpp
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#include <iostream>
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#include <vector>
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using namespace std;
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//插入排序
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/**
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* 将数组分为已排序和未排序的两部分,每次从未排序中选取一个元素,将他插入到已排序的的部分的正确位置
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*/
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vector<int> MySort(vector<int>& arr) {
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int n = arr.size();
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//arr[0]是已排好序的
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for(int i = 1; i < n; i++)
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{
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int key = arr[i];//我们要排序的元素
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int j = i-1;//已排好序的部分是[0,j]
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while(j >= 0 &&arr[j]>key)
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{
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arr[j+1] = arr[j];
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j--;
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}
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arr[j+1] = key;//j有可能<0,这么看来+1也就记住了吧
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}
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return arr;
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}
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int main()
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{
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vector<int> arr{5,2,3,1,4};
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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cout<<" "<<endl;
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MySort(arr);
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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return 0;
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}
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```
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## 4.归并排序
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```cpp
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#include <iostream>
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#include <vector>
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using namespace std;
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//归并排序
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vector<int> tmp;
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void merge_sort(vector<int>&q ,int l,int r)
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{
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if(l >= r) return;
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int mid = (l + r) >>1;
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merge_sort(q, l, mid);
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merge_sort(q, mid+1, r);
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int k = 0;//临时数组的下标
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int i = l , j = mid + 1;//i<=mid < mid+1<=r/////////////
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while(i <= mid && j <= r)//////////////
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{
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if(q[i] <= q[j])tmp[k++] = q[i++];
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else tmp[k++] = q[j++];
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}
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while(i<=mid){tmp[k++] = q[i++];}
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while(j<=r){tmp[k++] = q[j++];}
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for( i = l ,j = 0 ; i <= r ; i++,j++)q[i] = tmp[j];
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}
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vector<int> MySort(vector<int>& arr) {
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int n = arr.size();
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tmp.resize(n,0);//初始化为n个元素且都为0
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merge_sort(arr, 0, n-1);//0,n-1是下标
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return arr;
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}
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int main()
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{
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vector<int> arr{5,2,3,1,4};
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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cout<<" "<<endl;
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MySort(arr);
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for(auto it : arr)
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{
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cout<<it<<" ";
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}
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return 0;
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}
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```
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## 5.快速排序
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```cpp
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//快速排序
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void quick_sort(vector<int>&q,int l ,int r)
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{
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if(l >= r)return;
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int x = q[(l+r)>>1], i=l-1 , j=r+1;//x是最中间的那个数,i要多往前走一步,j要多往后走1步
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while (i < j) {
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do i++ ; while(q[i] < x);
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do j-- ; while(q[j] > x);
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if(i<j) swap(q[i],q[j]);//快速排序比的是下标
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}
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quick_sort(q, l, j);
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quick_sort(q, j+1, r);
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}
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vector<int> MySort(vector<int>& arr) {
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int n = arr.size();
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quick_sort(arr,0,n-1);
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return arr;
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}
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```
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## 6.希尔排序(了解)
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希尔排序是插入排序的一种优化,
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他的核心思想是假定原数组中间间隔着特定的增量,然后通过对组内的元素进行插入排序,
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不断缩小增量序列,从而达到有序的状态.
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我只了解过基本的原理,并没有实际使用过.
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## 7.堆排序(了解)
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堆排序是基于二叉堆数据结构的一种比较排序算法。二叉堆是一种完全二叉树,其中每个父节点的值都大于或等于(小于或等于)其子节点的值,称为最大堆(最小堆)。
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堆排序算法的基本思想是将待排序的数组构造成一个最大堆,然后不断调整堆,进行下沉操作,直到数组有序。
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堆排序的优势在于其时间复杂度稳定为O(nlogn),不受输入数据的影响。而且不需要额外的存储空间。
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这个我也只是了解过基本的原理,并没有实际使用过.
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---
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## 反转链表
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[206. 反转链表](https://leetcode.cn/problems/reverse-linked-list/)
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```cpp
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class Solution {
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public:
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// ListNode* reverseList(ListNode* head) {
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// if(!head)return NULL;
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// auto a = head,b = head->next;
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// while(b)
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// {
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// auto c = b->next;
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// b->next= a;
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// a = b;
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// b = c;
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// }
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// head->next = NULL;
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// return a;
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// }
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ListNode * reverseList(ListNode * head)
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{
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if(!head || !head->next)return head;
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auto tail = reverseList(head->next);
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head->next->next = head;
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head->next = NULL;
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return tail;
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}
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};
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```
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## 层序遍历
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[102. 二叉树的层序遍历](https://leetcode.cn/problems/binary-tree-level-order-traversal/)
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```cpp
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class Solution {
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public:
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vector<vector<int>> levelOrder(TreeNode* root) {
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vector<vector<int>>res;
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if(!root)return res;
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queue<TreeNode*>q;//中间变量
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q.push(root);
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while(!q.empty())
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{
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vector<int> level;//每一层的结点(要放到答案res里面的)
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int len = q.size();//这一层的节点个数
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while(len --)
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{
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auto t = q.front();
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q.pop();
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level.push_back(t->val);
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//未下一层做准备
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if(t->left)q.push(t->left);
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if(t->right)q.push(t->right);
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}
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res.push_back(level);
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}
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return res;
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}
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};
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```
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